IV ATP Potentiates Midazolam Sedation as Assessed by Bispectral Index
In this study, by measuring bispectral index (BIS), we tested the hypothesis that intravenous adenosine 5′-triphosphate (ATP) infusion would deepen the level of midazolam-induced sedation. Ten healthy volunteers underwent 2 experiments with at least 2 weeks' interval: immediately after intravenous bolus administration of midazolam (0.04 mg/kg), they received continuous infusion of either ATP infusion (100 μg/kg/min) or placebo (saline) for 40 minutes in a double-blind, randomized, crossover manner. Changes in BIS values and responsiveness to verbal command as well as cardiorespiratory variables were observed throughout the study periods. Administration of midazolam alone reduced BIS value from control: 97 ± 1 to 68 ± 18 at 25 minutes, which was accompanied by significant cardiopulmonary depressant effects, while maintaining responsiveness to verbal command (consciousness) throughout the study period. Coadministration of ATP with midazolam further reduced BIS value to 51 ± 13, associated with complete loss of consciousness without adverse effect on the cardiorespiratory systems. We conclude that the addition of ATP infusion to midazolam significantly enhances midazolam sedation without disturbing cardiorespiratory functions.Abstract

Intravenous adenosine 5′-triphosphate (ATP) potentiates midazolam sedation in healthy volunteers. Data are presented as mean ± SD, n = 10. *P < .05 midazolam + saline versus midazolam + ATP. BIS indicates bispectral index.

Change in hemodynamic variables. Data are presented as mean ± SD, n = 10. *P < .05 versus baseline control. SBP indicates systolic blood pressure; DBP, diastolic blood pressure; and HR, heart rate.

A. Change in respiratory variables: respiratory rate (RR), tidal volume (TV), minute ventilation (VE). Data are presented as mean ± SD, n = 10. *P < .05 versus baseline control. B. Change in respiratory variables: oxygen saturation (SpO2), end-tidal carbon dioxide (ETCO2). Data are presented as mean ± SD, n = 10. *P < .05 versus baseline control.
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